代写program、Python，c++编程语言代做

日期：2024-02-01 09:21

Exercise 1: Understanding TCP Congestion Control

using ns-2

We have studied the TCP congestion control algorithm in detail in the lecture (and

Section 3.6 of the text). You may wish to review this before continuing with this exercise.

Recall that, each TCP sender limits the rate at which it sends traffic as a function of

perceived network congestion. We studied three variants of the congestion control

algorithm: TCP Tahoe, TCP Reno and TCP new Reno.

We will first consider TCP Tahoe (this is the default version of TCP in ns-2). Recall that

TCP Tahoe uses two mechanisms:

? A varying congestion window, which determines how many packets can be sent

before the acknowledgment for the first packet arrives.

? A slow-start mechanism, which allows the congestion window to increase

exponentially in the initial phase, before it stabilises when it reaches threshold

value. A TCP sender re-enters the slow-start state whenever it detects

congestion in the network.

The provided script, tpWindow.tcl implements a simple network that is illustrated in the

figure below.

Node 0 and Node 1 are connected via a link of capacity 1 Mbps. Data traffic will only

flow in the forward direction, i.e. from Node 0 to Node 1. Observe that packets from

node 0 are enqueued in a buffer that can hold 20 packets. All packets are of equal size

and are equal to the MSS.

The provided script accepts two command line arguments:

? the maximum value of the congestion window at start-up in number of packets

(of size MSS).

? The one-way propagation delay of the link

You can run the script as follows:

$ns tpWindow.tcl <max_cwnd> <link_delay>

NOTE: The NAM visualiser is disabled in the script. If you want to display the NAM

window (graphical interface), then uncomment the fifth line of the 'finish' procedure (i.e.

remove the "#"):

proc finish {} {

global ns file1 file2

$ns flush-trace

close $file1

close $file2

#exec nam out.nam &

exit 0

}

We strongly recommend that you read through the script file to understand the

simulation setting. The simulation is run for 60 seconds. The MSS for TCP segments is

500 bytes. Node 0 is configured as a FTP sender which transmits a packet every 0.01

second. Node 1 is a receiver (TCP sink). It does not transmit data and only

acknowledges the TCP segments received from Node 0.

The script will run the simulation and generate two trace files: (i) Window.tr, which keeps

track of the size of the congestion window and (ii) WindowMon.tr , which shows several

parameters of the TCP flow.

The Window.tr file has two columns:

time congestion_window_size

A new entry is created in this file every 0.02 seconds of simulation time and records the

size of the congestion window at that time.

The WindowMon.tr file has six columns:

time number_of_packets_dropped drop_rate throughput queue_size avg_tp

ut

A new entry is created in this file every second of simulation time.

The number_of_packets_dropped , drop_rate and throughputrepresent the

corresponding measured values over each second. The queue_size indicates the size of

the queue at each second, whereas avg_tput is the average throughput measured since

the start of the simulation.

Question 1 : Run the script with the max initial window size set to 150 packets and the

delay set to 100ms (be sure to type "ms" after 100). In other words, type the following:

$ns tpWindow.tcl 150 100ms

To plot the size of the TCP window and the number of queued packets, we use the

provided gnuplot script Window.plot as follows:

$gnuplot Window.plot

What is the maximum size of the congestion window that the TCP flow reaches in this

case? What does the TCP flow do when the congestion window reaches this value?

Why? What happens next? Include the graph in your submission report.

Question 2: From the simulation script we used, we know that the payload of the

packet is 500 Bytes. Keep in mind that the size of the IP and TCP headers is 20 Bytes,

each. Neglect any other headers. What is the average throughput of TCP in this case?

(both in number of packets per second and bps)

You can plot the throughput using the provided gnuplot script WindowTPut.plot as

follows:

$gnuplot WindowTPut.plot

This will create a graph that plots the instantaneous and average throughput in

packets/sec. Include the graph in your submission report.

Question 3 : Rerun the above script, each time with different values for the max

congestion window size but the same RTT (i.e. 100ms). How does TCP respond to the

variation of this parameter? Find the value of the maximum congestion window at which

TCP stops oscillating (i.e., does not move up and down again) to reach a stable behaviour.

What is the average throughput (in packets and bps) at this point? How does the actual

average throughput compare to the link capacity (1Mbps)?

TCP Tahoe vs TCP Reno

Recall that, so far we have observed the behaviour of TCP Tahoe. Let us now observe

the difference with TCP Reno. As you may recall, in TCP Reno, the sender will cut the

window size to 1/2 its current size if it receives three duplicate ACKs. The default

version of TCP in ns-2 is TCP Tahoe. To change to TCP Reno, modify the Window.tcl

OTcl script. Look for the following line:

set tcp0 [new Agent/TCP]

and replace it with:

set tcp0 [new Agent/TCP/Reno]

Question 4 : Repeat the steps outlined in Questions 1 and 2 (NOT Question 3) but for

TCP Reno. Compare the graphs for the two implementations and explain the

differences. (Hint: compare the number of times the congestion window goes back to

zero in each case). How does the average throughput differ in both implementations?

Note: Remember to include all graphs in your report.

Exercise 2: Flow Fairness with TCP

In this exercise, we will study how competing TCP flows with similar characteristics

behave when they share a single bottleneck link.

The provided script, tp_fairness.tcl generates 5 source-destination pairs which all share

a common network link. Each source uses a single TCP flow which transfers FTP traffic

to the respective destination. The flows are created one after the other at 5-second

intervals (i.e., flow i+1 starts 5 seconds after flow i for i in [1,4] ). You can invoke the

script as follows

$ns tp_fairness.tcl

The figure below shows the resulting topology; there are 5 sources (2,4,6,8,10), 5

destinations (3,5,7,9,11), and each source is sending a large file to a single destination.

Node 2 is sending a file to Node 3, Node 4 is sending a file to Node 5, and so on.

The script produces one output file per flow; farinessMon i .tr for each i in [1,5] . Each of

these files contains three columns:

time | number of packets delivered so far | throughput (packets per second)

You can plot the throughput as a function of time using the provided gnuplot

script, fairness_pps.plot , as follows:

$gnuplot fairness_pps.plot

NOTE: The NAM visualiser is disabled in the script. If you want to display the NAM

window (graphical interface), modify tp_fairness.tcl and uncomment the fifth line of the

'finish' procedure:

proc finish {} {

global ns file1 file2

$ns flush-trace

close $file1

close $file2

#exec nam out.nam &

exit 0

}

Run the above script and plot the throughput as a function of time graph and answer the

following questions:

Question 1 : Does each flow get an equal share of the capacity of the common link (i.e.,

is TCP fair)? Explain which observations lead you to this conclusion.

Question 2. What happens to the throughput of the pre-existing TCP flows when a new

flow is created? Explain the mechanisms of TCP which contribute to this behaviour.

Argue about whether you consider this behaviour to be fair or unfair.

Note: Remember to include all graphs in your report.

Exercise 3: TCP competing with UDP

In this exercise, we will observe how a TCP flow reacts when it has to share a bottleneck

link that is also used by a UDP flow.

The provided script, tp_TCPUDP.tcl , takes a link capacity value as a command line

argument. It creates a link with the given capacity and creates two flows which traverse

that link, one UDP flow and one TCP flow. A traffic generator creates new data for each

of these flows at a rate of 4Mbps. You can execute the simulation as follows,

$ns tp_TCPUDP <link_capacity>

After the simulation completes, you can plot the throughput using the provided gnuplot

script, TCPUDP_pps.plot , as follows,

$gnuplot TCPUDP_pps.plot

Question 1: How do you expect the TCP flow and the UDP flow to behave if the

capacity of the link is 5 Mbps?

Now, you can use the simulation to test your hypothesis. Run the above script as

follows,

$ns tp_TCPUDP.tcl 5Mb

The script will open the NAM window. Play the simulation. You can speed up the

simulation by increasing the step size in the right corner. You will observe packets with

two different colours depicting the UDP and TCP flow. Can you guess which colour

represents the UDP flow and the TCP flow respectively?

You may disable the NAM visualiser by commenting the "exec nam out.nam &' line in

the 'finish' procedure.

Plot the throughput of the two flows using the above script (TCPUDP_pps.plot) and

answer the following questions:

Question 2: Why does one flow achieve higher throughput than the other? Try to

explain what mechanisms force the two flows to stabilise to the observed throughput.

Question 3: List the advantages and the disadvantages of using UDP instead of TCP for

a file transfer, when our connection has to compete with other flows for the same link.

What would happen if everybody started using UDP instead of TCP for that same

reason?

Note: Remember to include all graphs in your report.

BONUS Exercise: Understanding IP Fragmentation

(Optional: If you attempt this and Include it in your report, you may get bonus marks

(max of 2 marks). We will add these bonus marks to your Lab total with the condition

that the total obtained marks for the labs cannot exceed 20)

We will try to find out what happens when IP fragments a datagram by increasing the

size of a datagram until fragmentation occurs. You are provided with a Wireshark trace

file ip_frag that contains trace of sending pings with specific payloads to 8.8.8.8. We

have used ping with option ( – s option on Linux) to set the size of data to be carried in

the ICMP echo request message. Note that the default packet size is 64 bytes in Linux

(56 bytes data + 8 bytes ICMP header). Also note that Linux implementation for ping

also uses 8 bytes of ICMP time stamp option leaving 48 bytes for the user data in the

default mode. Once you have send a series of packets with the increasing data sizes, IP

will start fragmenting packets that it cannot handle. We have used the following

commands to generate this trace file.

Step 1: Ping with default packet size to the target destination as 8.8.8.8

ping -c 10 8.8.8.8

Step 2: Repeat by sending a set of ICMP requests with data of 2000.

ping -s 2000 -c 10 8.8.8.8

Step 3: Repeat again with data size set as 3500

ping -s 3500 -c 10 8.8.8.8

Load this trace file in Wireshark, filter on protocol field ICMP (you may need to clear the

filter to see the fragments) and answer the following questions.

Question 1: Which data size has caused fragmentation and why? Which host/router has

fragmented the original datagram? How many fragments have been created when data

size is specified as 2000?

Question 2: Did the reply from the destination 8.8.8.8. for 3500-byte data size also get

fragmented? Why and why not?

Question 3: Give the ID, length, flag and offset values for all the fragments of the first

packet sent by 192.168.1.103 with data size of 3500 bytes?

Question 4: Has fragmentation of fragments occurred when data of size 3500 bytes has

been used? Why and why not?